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How can I find the 3 first letters from the name file

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# 1  
Old 06-16-2005
How can I find the 3 first letters from the name file
Hello,

I have a name file in Unix for example : ABC_TODAYFirst.001 and I want just capture or display the 3 first letters so : ABC.

I tried with cut -c,1-3 and the name but it displays the 3 first letters of all lines.

Can you help , Thanks a lot
# 2  
Old 06-16-2005
this is confusing..... what does it mean 'it displays the 3 first letters of all lines."?
could you show what you have so far together with sample input and the desired output, pls!
# 3  
Old 06-16-2005
the 3 first letters from the name file
Hello,

Thanks no the problem is I want just display the 3 first letters of the name file.

So for toto.txt , it must display tot

Thanks.
# 4  
Old 06-16-2005
Quote:
Originally Posted by steiner
Hello,

Thanks no the problem is I want just display the 3 first letters of the name file.

So for toto.txt , it must display tot

Thanks.
echo 'toto.txt' | sed 's/^\(...\).*/\1/'
# 5  
Old 06-16-2005
If you mean the first three letters of the files name:

Code:
# filename="abcdefghi"
# print - "${filename%${filename#???}}"
abc

In case you want the first three letters of every line in a given file use sed:

Code:
sed 's/^\(...\).*$/\1/' <filename>

Hope this helps

bakunin
This User Gave Thanks to bakunin For This Post:
chacko193
# 6  
Old 06-16-2005
i dont speak english well but i think you need es to get the 3 first letters of a list of files right?

like in your first post, if the 4th letter is '_' do this:

Code:
ls -1 | cut -d "_" -f1 > newfile

and you will get what you want in 'newfile' or obmit '> newfile' and you will get what you want in screen.

Lestat
# 7  
Old 06-16-2005
Another thing, i dont understanw well the part of "but it displays the 3 first letters of all lines" that you post, please tell me exactly what kind of files do you have and what exactly you want as output

Lestat
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