shell scripting


 
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# 1  
Old 07-21-2012
shell scripting

hey I am new to shell scripting please help me.

we have to create 2 or 3 tables in the file.txt format i.e.,
file name like ABC.txt, abs1.txt....

Name Empid Mangerid Adrress
abc 1 11 hyd
efg 2 11 hyd

like this we have to create.

this are input source.
we have to get the out put has
in output source file.ksh(abc.txt) only two columns we have to display.

Name Mangerid
abc 11
efg 11

Please help for this... its urgent.
# 2  
Old 07-21-2012
Dude, try to write more clear! It's hard to understand what you want to do!

If you have the input file and you wanna print just 2 columns of it , you can use this:
Code:
awk '{print $1 "\t" $3}' inputfile.txt > output.txt'

This will print the first and third column of your input file to the output file.
# 3  
Old 07-21-2012
I have multiple text files (tab delimited) - all with four columns - id, name, salary and department.

Column order in each txt file is not guarenteed.

I need to write a Korn shell script which takes one of the file name as input and returns id and department columns as output.

I am not sure about how to return those two specific columns considering that the order of those two columns is not same for the input file that gets passed and so I am assuming I cannot use fixed ordinal position (like $1 or $3..). Is there a way I can read the data from file based on column names instead of ordinal positions (my input text file can contain column headers).

Any help in this regard would be greatly appreciated. Thanks!
# 4  
Old 07-21-2012
This isn't homework, is it?
# 5  
Old 07-21-2012
It's pretty straight forward to treat the first record of the input file as a header and use those labels to identify the columns. This assumes that there aren't any spaces in the headers:

Code:
awk '
    NR == 1 {
        for( i = 1; i <= NF; i++ )    # create map, column name to number
            col[$(i)] = i;
        next;
    }

    # for all other records, print the desired data from the columns
    { printf( "%s %s\n", $(col["Name"]), $(col["Mangerid"]) ); }
'  input-file >output-file

Hope this gets you a bit further.

Last edited by agama; 07-21-2012 at 11:30 AM.. Reason: better comment
# 6  
Old 07-22-2012
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