Shell Programming and Scripting

Dear Friends,

You can easily understand my problem after looking into the code.

test1.sh
--------
#!/bin/sh
LOG_HOME="/home/vel"
while [ TRUE ]
do
echo `date`
done

test2.sh
--------
#!/bin/sh
LOG_HOME="/home/vel"
if [ -s $LOG_HOME/1.log ]
then
sh $LOG_HOME/test1.sh >> $LOG_HOME/1.log
else
touch 1.log
sh $LOG_HOME/test1.sh >> $LOG_HOME/1.log
fi

I will execute test2.sh script. After sometime I will move the 1.log to another directory. The problem is the script is still appending the output of test1.sh to the moved file. It should not happen. 1.log should be newly created in the LOG_HOME and output should be appended to the newly created file.

I have tried some logic. But I couldnt find the solution for solving this problem. Can any one help me out from this?

Note: You can modify test2.sh only.

Thanks in Advance,
S.M.Vel

>> will append or if the file is not there then it creates it again newly. But, It will only append new informations not the old one. You can look it in the new file.

hth.

Why?!? This wouldn't happen to be a homework problem, would it?

ZB

Muthukumar,

It is appending only in the old file(which is moved to some directory).
Have you tried executing this code?
If you need some more clarification, tell me.

Problem is because of inifite loop in test1.sh. It will keep on appending date informations in to 1.log. It will update the file of 1.log if you move anywhere. Operation is being done with kernel level to update a log file, we can not control from user level by changing locaiton of file.

hth.

Thanks Muthukumar for making clear about the problem from user level.

Regards,
S.M.Vel