Shell Programming and Scripting

Yes, i can: the problem is your following line:

Code:

V1=`sed -n \'$st\;$ed\' \< $F1`

Presumably i would work with a generous dose "eval"-statements, because the problem is: the shell is aware of what a parameter to a command is and per definitionem an expanded variable is such a parameter. Therefore you don't need the single quotes one usually encloses his sed-statements in. Here is a basic alternative to your script which works as a pipeline filter:

Code:

#!/bin/ksh

typeset -i iBegin=$1
typeset -i iEnd=$1
typeset    chSedCmd=""

(( iEnd += 1 ))
chSedCmd="${iBegin}p;${iEnd}q"

sed -n $chSedCmd

exit 0

use with "cat <file> | <scriptname> <number>" where "<number>" is the number you want to display. My first take was:

Code:

chSedCmd="\'${iBegin}p;${iEnd}q\'"

and it produced the same error as your script: "function ... can not be parsed". The same happened with

Code:

chSedCmd="'${iBegin}p;${iEnd}q'"

When I removed the single quotes from the string it worked.

Hope this helps.

bakunin

Instead of
V1=`sed -n \'$st\;$ed\' \< $F1`

Use following syntax :
V1=`sed -n "$st;$ed" $F1`

It should work.