Shell Programming and Scripting

Originally Posted by jim mcnamara

We cannot know without seeing what the script's code does with parameters.

undef($result);

$cpu /= $i;

# Plugin return code
my $status = "OK";
if ($cpu >= $opt_c) {
$status = "CRITICAL";
} elsif ($cpu >= $opt_w) {
$status = "WARNING";
}

my $str = "CPU utilization percentage : ".$cpu."%|avg=".$cpu."%";
if ($opt_l == 0) {
for ($i = 0; defined($cpulist[$i]); $i++){
$str .= " cpu$i=".$cpulist[$i]."%";
}
}

# Display Ouptut
print $str."\n";
undef($str);
exit $ERRORS{$status};

sub print_usage () {
print "\nUsage:\n";
print "$PROGNAME\n";
print "This Plugin is design for return CPU percent on windows Serveurs (1 min Average)\n";
print "\n";
print " -H (--hostname) Hostname to query - (required)\n";
print " -C (--community) SNMP read community (defaults to public,\n";
print " -c (--critical) Three critical tresholds (defaults : 95)\n";
print " -w (--warning) Three warning tresholds (defaults : 90)\n";
print " -l Display only cpu average\n";
print " -v (--snmp_version) 1 for SNMP v1 (default)\n";
print " 2 for SNMP v2c\n";
print " -k (--key) snmp V3 key\n";
print " -p (--password) snmp V3 password\n";
print " -u (--username) snmp v3 username \n";
print " -V (--version) Plugin version\n";
print " -h (--help) usage help\n";
}



sub print_help () {
print
print_usage();
print "\n";
}