Shell Programming and Scripting

Hey all,

Tried searching the forums but my search-fu may not be strong today; please feel free to redirect me if I have simply missed a post that would be helpful!

Trying to create a while loop that reads a list of configuration files, checks for a line that starts with "SOME_CMD" and ends with ".ext", and then if it does have that, echoes back the name of the configuration file.

When I try to input this on the command line, I receive this message:
ksh: syntax error: `fi' unexpected

(We're using the old ksh on Solaris, not the 93. Not fully sure that makes a difference, but it might.)

While I'm pretty sure that I'm missing something small, I'm new enough to Unix and while loops that I can't see it myself. A coworker has looked over it and we're both unsure what I missed. I've even tried to google this with little luck.

Please, could you point out what I might have forgotten/missed?

"then" is missing after second "if" condition.

also you can reduce some code by using following

Code:

grep "^SOME_CMD.*ext$" infile

Why do you want to echo the config file name on match found ?

Oh! Hahaha. That would do it. Thanks!

Or even:

Code:

ls -1d *.cfg | while read cfg
do
     grep -q '^SOME_CMD=/usr/path/file.ext$' ${cfg}
     echo $?
     if [[ $? == 0 ]]
     then
          echo "${cfg}"
     fi
done

There is no need for the -1 option since ls is not sending its output to the terminal. In fact, there is no need for ls at all:

Code:

for cfg in *.cfg
do
  : whatever ...
done