sed or awk command to replace a string pattern with another string based on position of this string


 
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Old 06-14-2012
sed or awk command to replace a string pattern with another string based on position of this string

here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb

Code:
 
cat dump.sql
 
INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10 13:00:00'),(2,'dsfsd','2000-04-06 00:00:00','Updated','2011-02-10 13:00:00'),(3,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10 13:00:00')
.
.
.
INSERT INTO `table2` (`id`, `action`, `date`, `lastModified`, `dynamics`) VALUES (1,'Change','2011-05-05 00:00:00','2012-02-10 13:00:00',null),(2,'dsfsd','2000-04-06 00:00:00','2011-02-10 13:00:00',null),(3,'Change','2011-05-05 00:00:00','2012-02-10 13:00:00',123)
.
 
.
.many tables


the above are just sample data... here some table lastModified field can be at end or somewhere in between.... what i want to achieve is replace all corresponding lastModifed parameter with '0000-0000 00:00:00' instead of exisiting values. i can make this by directly updating it in database but i want to modify it directly it in this dump file rather than updating it in database first and then taking the dump. so is this feasible..? the logic should happen like this it should compare from one "INSERT INTO" to next INSERT INTO and between this from find the position of last modified and replace it with 000's.. but a table can have many timestamp parameter. but the command or script should modify only the corresponding lastModified column. any help would be appreciated.
 
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