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Remove lines between "###"

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# 1  
Old 05-28-2012
Remove lines between "###"
i have a file as below:
Code:
12 23 25 
12 22 
12 33 32 
###
12 23 56 45 77 45 56
12 54 6
###
###
1254
###

i named anything between two tandem "###" as a section, now i want to remove any section that has less than 2 lines. i wrote somthing like this code but i dont know how can i remove that section
Code:
awk '/###/ NR=x {while($1!~/###/getline;next NR=y} in > out

i think this code can compute the number of line of each section so i must write a code if y-x<4 for each section, remove that.
# 2  
Old 05-28-2012
Hi

Is this what you expected?


Code:
$ awk '/###/{if(i>=2)for(j=0;j<i;j++)print a[j];print;i=0;next}{a[i++]=$0;}' a
12 23 25
12 22
12 33 32
###
12 23 56 45 77 45 56
12 54 6
###
###
###

Guru
This User Gave Thanks to guruprasadpr For This Post:
saeed.soltani
# 3  
Old 05-28-2012
yes thank you but there is a little problem can we remove extra "###" . for example here at the end there is 3 of that.it'll be more convenient if it can be removed when the data is very long in a file.
# 4  
Old 05-28-2012
Alternatively:
Code:
awk '/###/{print (n>1?p:x) $0; p=n=x; next}{p=p $0 RS; n++}' infile

or
Code:
awk '/###/{if (n>1) print p $0; p=n=x; next}{p=p $0 RS; n++}' infile

Provided input files end with a ### line, otherwise there has to be an END section too.


--
This might work too:
Code:
awk -F'\n' 'END{printf "\n"} NF>3' RS=# ORS=### infile

Last edited by Scrutinizer; 05-28-2012 at 11:36 AM..
This User Gave Thanks to Scrutinizer For This Post:
saeed.soltani
# 5  
Old 05-28-2012
Thank you very much. it works perfect!
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