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egrep -i "(from|to)=<$1>" mail.log ?

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# 1  
Old 05-04-2012
egrep -i "(from|to)=<$1>" mail.log ?
Hi,

As you can see I'm trying to get email addresses from the mail.log.

This is a part of a bash shell script I found but I#m wondering how I can check the
variable $1?
When I try
Code:
egrep -i "(from|to)=<$1>" mail.log | awk ' {print $1}'

either from the command line or from a script it doesn't print nothing

Can someone explain me that please?

Thanks
Last edited by Franklin52; 05-04-2012 at 06:36 AM.. Reason: Please use code tags
# 2  
Old 05-04-2012
Please post few lines from mail.log and the desired output. You'll receive quicker responses.
# 3  
Old 05-04-2012
Ok, sorry!

here is an example entry:
Code:
May  3 00:00:29 prx1-mgmt postfix/qmgr[3781]: 88BFC2FB802: from=<double-bounce@prx1.example.com>, size=288, nrcpt=1 (queue active)

So I think $1 should contain "double-bounce@prx1.example.com", right?
Last edited by Franklin52; 05-04-2012 at 06:37 AM.. Reason: Please use code tags for data and code samples
# 4  
Old 05-04-2012
What does not work? What is your OS and version?
Code:
$ echo "$1"
double-bounce@prx1.example.com
$ echo 'May  3 00:00:29 prx1-mgmt postfix/qmgr[3781]: 88BFC2FB802: from=<double-bounce@prx1.example.com>, size=288, nrcpt=1 (queue active)' |
> grep -Ei "(from|to)=<$1>"
May  3 00:00:29 prx1-mgmt postfix/qmgr[3781]: 88BFC2FB802: from=<double-bounce@prx1.example.com>, size=288, nrcpt=1 (queue active)
$

# 5  
Old 05-04-2012
Code:
 
nawk -F"[<>]" '/from/ || /to/ {print $2}' mail.log

# 6  
Old 05-04-2012
The awk cmd is not that important here.

It just picks up a field from the lines matching the regex in the egrep command.

What I'm wondering about is what's the meaning of the $1 variable in the egrep command.
Normally in the regexp (Perl) I use this:
Code:
egrep -i "(from|to)=<(.*)>" mail.log

if I want to store the contents inside <> and access it then by $1.
Maybe that that confuses me a bit Smilie


Even if (in my opinion) it's not that important in this case, I'm using a RHEL 5.8
Last edited by Franklin52; 05-04-2012 at 09:46 AM.. Reason: Code tags
# 7  
Old 05-04-2012
Ah, now I see what you are trying to do. No grep does not work that way... The $1 is a shell (positional) parameter and it has nothing to do with grep....
It is possible to use back references in egrep, but only to aid in matching, for example:
Code:
$ echo blargdgddd | grep -E '(bla).*\1'
$ echo blagdfgdbla | grep -E '(bla).*\1'
blagdfgdbla

Last edited by Scrutinizer; 05-04-2012 at 10:01 AM..
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