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Terminate left side portion of a string

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# 1  
Old 05-03-2012
Terminate left side portion of a string
I have a awk file which consists of the follwoing code in file select.awk :
Code:
/xxx/ {
        time = gensub(/xxx \*\*\*(.*)/, "\\1", "g")
        printf("%s\n",time)
        next
}

and an input file with the following file file.txt :-

HTML Code:
xxx ***Wed May 2 18:00:00 CDT 2012
AAA AAAA AAAA xxx ***Wed May 2 18:00:05 CDT 2012
AA xxx ***Wed May 2 18:00:10 CDT 2012
xxx ***Wed May 2 18:00:15 CDT 2012
0.00          0.00xxx ***Wed May 2 18:00:20 CDT 2012
when i execute it like this . it shows below o/p:-
Code:
sed -n "p" file.txt | awk -f select.awk

gives me

Code:
Wed May 2 18:00:00 CDT 2012
AAA AAAA AAAAWed May 2 18:00:05 CDT 2012
AAWed May 2 18:00:10 CDT 2012
Wed May 2 18:00:15 CDT 2012
0.00          0.00xxx ***Wed May 2 18:00:20 CDT 2012


I am trying to delete the left part of the string which comes after xxx *** and including xxx ***.

O/p should be only the data format in every line rest all should be eliminated but as the current code uses replace for xxx *** it only erases those but no the left part of it .

Code:
Wed May 2 18:00:00 CDT 2012
Wed May 2 18:00:05 CDT 2012
wed May 2 18:00:10 CDT 2012
Wed May 2 18:00:15 CDT 2012
Wed May 2 18:00:20 CDT 2012

can someone tell me how can i do that

Moderator's Comments:
Mod Comment Welcome to the UNIX and Linux Forums. Please use [code][/code] tags. Video tutorial on how to use them
Last edited by Scrutinizer; 05-03-2012 at 02:40 AM.. Reason: mistakes - mod: Some more code tags...
# 2  
Old 05-03-2012
with sed

Code:
sed 's/.*\*\*\*\(.*\)/\1/g' filename.txt

---------- Post updated at 01:41 PM ---------- Previous update was at 01:39 PM ----------

with awk

Code:
 awk -vFS="\*\*\*" '{print $2}' filename.txt

# 3  
Old 05-03-2012
This works but I am looking to use a string manipulation function to get this done.


Code:
/xxx/ {         time = gensub(/xxx \*\*\*(.*)/, "\\1", "g")         printf("%s\n",time)         next }

As gensub is not working for me can you help me out how to use a split function or substr function to get the same results .
Last edited by shikshavarma; 05-03-2012 at 09:56 PM.. Reason: code tags missing
# 4  
Old 05-03-2012
Try this:

Code:
/xxx/ { gsub(/^.*xxx \*\*\*/, "",$0); print }

This User Gave Thanks to Chubler_XL For This Post:
shikshavarma
# 5  
Old 05-03-2012
Thank's a lot .that's all i was looking for it rocks now.
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