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Help with for/if/else print statements

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# 1  
Old 03-14-2012
Help with for/if/else print statements
Code:
{for(i in b){if(b[i]-1&&a[i]!=b[i]){print i";\t\t"b[i]}else{print "NEW:"i";\t\t"b[i]} } }

what I need is to just print

Code:
else{print "NEW:"i";\t\t"b[i]

and not print

Code:
{print i";\t\t"b[i]}

how do i get awk to not print the first bit? is there an ignore statement although i still need awk to use this statement for the calculation in

Code:
else{print "NEW:"i";\t\t"b[i]

if you understand the logic
# 2  
Old 03-14-2012
Just remove the code from the fist part:
Code:
{for(i in b){if(b[i]-1&&a[i]!=b[i]){}else{print "NEW:"i";\t\t"b[i]} } }

This User Gave Thanks to bartus11 For This Post:
slashbash
# 3  
Old 03-14-2012
great it works, I was missing the

Code:
{}

---------- Post updated at 08:56 PM ---------- Previous update was at 08:55 PM ----------

any chance you could answer my other post

https://www.unix.com/shell-programmin...uirements.html
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