Shell Programming and Scripting

Hey guys,

I've got an awk string that does a simple calculation which works well. However, I'd really like to be able to strip the decimal point and the trailing ints from it - any ideas on how I'd change the awk string to be able to do that ? I've changed it countless times and each time it still won't work, it's driving me insane!

Anyway, here's my simple calculation:

Code:

awk "BEGIN{print ${ARR[21]} / ${ARR[19]}}"

As you can see, it's pretty simple and works well, just can't figure out how to change it to give a simple result rather than 93.992829292828 for example!

Thanx

Jim

Hi jimbob01,

This seemed to work. Is useful for you too?

Code:

$ awk 'BEGIN { printf "%d\n", 93.992829292828 }'

Hi birei,

Thanks for your reply.

I've tried something similar before, but I'm doing a calculation of two integer values in an array. I've got a script that runs that takes data into a file and then reports it and it runs every 5 minutes so the values in the arrays change constantly.

Any ideas on how I would be able to do it while using the values in an array ?


Thanx

Jim

Regards,
Alister

Sorry Alister, but you've just confused me!

Code:

awk "BEGIN{printf "%d\n",${ARR[21]} / ${ARR[19]}}"

Code:

awk "BEGIN{print int(${ARR[21]} / ${ARR[19]})}"

But you do not need awk, you can just do it in shell:

Code:

echo "$(( ${ARR[21]} / ${ARR[19]} ))"

For floating point you will use printf with %f

Code:

awk 'BEGIN { printf ("%.2f\n",93.946) } '
93.95

Hope that helps
Regards
Peasant.