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# 1  
Old 12-27-2011
Help Moving lines
Hi,

I tried going through the existing threads, but couldn't find a solution to my problem. My input file is:

Code:
199.15.2.7|gxi.wxxx.com/|(Mozilla/4.0)|
ASCII text|950604ad05
70.38.9.7|mmg10.com/2011/1.gif|(Mozilla/4.0)|
application/x-ms-dos-executable|a2f332Y02d0
70.38.9.2|vim105.com/113856471.gif|(Mozilla/4.0)|
application/x-ms-dos-executable|aed7d0cK80a0

My output file should look like:
Code:
199.15.2.7|gxi.wxxx.com/|(Mozilla/4.0)|ASCII text|950604ad05
70.38.9.7|mmg10.com/2011/1.gif|(Mozilla/4.0)|application/x-ms-dos-executable|a2f332Y02d0
70.38.9.2|vim105.com/113856471.gif|(Mozilla/4.0)|application/x-ms-dos-executable|aed7d0cK80a0

How do I do this in sed or awk? It should look for the | symbol at end of line, and if it is present, bring the line below that up.

Any help with explanation would be appreciated
# 2  
Old 12-27-2011
Try:
Code:
awk 'ORS=NR%2 ? " " : "\n"' file

# 3  
Old 12-27-2011
Code:
perl -pe '/\|$/&&s/\n$//' inputfile

/\|$/ --> Searches for | symbol at the end of line
&& --> logical 'and' operator.
s/\n$// --> Replace \n at the end with null
This User Gave Thanks to balajesuri For This Post:
r4v3n
# 4  
Old 12-27-2011
Thank you both.

Both solutions worked, but am going with balajesuri's code because I understood his explanation Smilie
# 5  
Old 12-27-2011
Quote:
Originally Posted by balajesuri
Code:
perl -pe '/\|$/&&s/\n$//' inputfile

/\|$/ --> Searches for | symbol at the end of line
&& --> logical 'and' operator.
s/\n$// --> Replace \n at the end with null
You can bypass the logical and by using:
Code:
 perl -pe 's/\|\s*\n/\|/' inputfile

# 6  
Old 12-27-2011
Another one...
Code:
awk '/^[0-9]/{printf $0;next}1' infile

--ahamed
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