Shell Programming and Scripting

Hi Friends,
Please help me to sort out this problem, I am running this in centos o/s and whenever I run this script I am getting "find: missing argument to `-exec' " but when I run the same code in the command line I didn't find any problem. I am using perl script to run this application.
Correct me if I am wrong any where.. This coding is to find the top 3 files in the filesystem with respect to size.

Code:

#!/usr/bin/perl
$get_filename=qx("find / -mmin 1 -type f -exec ls -lh {} \; 2>  /dev/null | awk '{ print $NF ": " $5 }'  | sort -nrk 2,2 |head -n3");
print "$get_filename \n";

Your feedback is appreciated on this

Moderator's Comments:

Use code tags please, ty. You'll get a PM with a guide.