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Shell Programming and Scripting

Search and Replace by record position

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# 8  
Old 11-02-2011
Should have been:
Code:
b1=$(printf %-11s "$b")

(without quotes, printf will treat $b's expansion to LAS VEGAS as 2 parameters and just re-uses the format arg for both)
# 9  
Old 11-02-2011
Thank you so much CarloM! I was wondering though what is it in the printf command that pads the data with space? I was wondering if say I wanted to pad with zero's instead of spaces. Smilie
# 10  
Old 11-02-2011
You can pad numbers with a format specifier like %03d, but iirc it doesn't work with strings - check the man page(s).
This User Gave Thanks to CarloM For This Post:
macastor
# 11  
Old 11-02-2011
Wrench
Ok thanks again CarloM for all your help. Smilie Have a good day.
# 12  
Old 11-02-2011
To make it easier and safer, maybe you sould consider formating your file with a separator at first (here an example with colon ":" as separator)

Code:
sed 's/PO BOX [0-9][0-9]*/:&:/;s/[^ ][^ ]*$/:&/;s/[ ]*:[ ]*/:/g' yourfile

All further processing can then easly be handled like changing the wanted field

Code:
nawk -F: -vNAME="BRAD PIT" -vCITY="LAS VEGAS" '$0~NAME{$3=CITY}1'

This User Gave Thanks to ctsgnb For This Post:
macastor
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