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1. Shell Programming and Scripting
Hi ALL,
I have been testing this script to run for every last Sunday of the month,looks like month which have 5 sunday (july 2016 )is not passing this and failing every time.
Here is what I am using,
current_date=31
echo " CURRENT DAY -> $current_date"
if
... (2 Replies)
Discussion started by: netdbaind
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2. Shell Programming and Scripting
I am looking for a unix script which could run a job on 2, 4 and 7 working day of the month.
if the days are falling on the saturday/sunday. it should run on the next day.
Thank you.. (9 Replies)
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3. Shell Programming and Scripting
Hi All,
Requirement :-
I have shell script in kern shell ,have to run alternate week per month
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4. Shell Programming and Scripting
Hi all,
I currently have a UNIX file maintenance script that runs daily as a cron job.
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5. Shell Programming and Scripting
Hello Experts,
I have a script which i want to run the on last day of every month.
let say I have backup.sh script which i want to run it every month last day.
Can anyone please help :confused:
thanks (4 Replies)
Discussion started by: aks_1902
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6. Shell Programming and Scripting
Hello All,
I am trying to come up with a shell script to count a specific word in a logfile on each day of this month, last month and the month before. I need to produce this report and email it to customer.
Any ideas would be appreciated! (5 Replies)
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7. Solaris
What should be the crontab entry in solaris to run a script on 1st of every month?
Is this correct?
00 02 1 * * <script to be executed> (5 Replies)
Discussion started by: deepaksahni0109
5 Replies
8. UNIX for Dummies Questions & Answers
I know I can't schedule this in cron and would have to write a wrapper around my script and schedule it in cron ....but not sure how do to this?
How do I exclude Monday if the 2nd day of the month falls on a Monday?
Thanks.
I tried this:
0 0 2 * 0,2-6 command
And I know this doesnt... (2 Replies)
Discussion started by: newtou
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9. UNIX for Advanced & Expert Users
Hello Friends,
In my project I have to schedule a script to be run on every second saturday (once in month). Can you please suggest what entry should I make in cron ? (5 Replies)
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10. UNIX for Advanced & Expert Users
Is there a utility that can be used in a shell script that would run a .sql file for 30 or 31 days in a month at the same time parallely. Please Advice.
Thanks
SD12. (2 Replies)
Discussion started by: sd12
2 Replies
CAL(1) BSD General Commands Manual CAL(1)
NAME
cal -- displays a calendar
SYNOPSIS
cal [-3hjry] [-A after] [-B before] [-d day-of-week] [-R reform-spec] [[month] year]
DESCRIPTION
cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-3 Same as ``-A 1 -B 1''.
-A after
Display after months after the specified month.
-B before
Display before months before the specified month.
-d day-of-week
Specifies the day of the week on which the calendar should start. Valid values are 0 through 6, presenting Sunday through Saturday,
inclusively. The default output starts on Sundays.
-h Highlight the current day, if present in the displayed calendar. If output is to a terminal, then the appropriate terminal sequences
are used, otherwise overstriking is used. If more than one -h is used and output is to a terminal, the current date will be high-
lighted in inverse video instead of bold.
-j Display Julian dates (days one-based, numbered from January 1).
-R reform-spec
Selects an alternate Gregorian reform point from the default of September 3rd, 1752. The reform-spec can be selected by one of the
built-in names (see NOTES for a list) or by a date of the form YYYY/MM/DD. The date and month may be omitted, provided that what is
specified uniquely selects a given built-in reform point. If an exact date is specified, then that date is taken to be the first
missing date of the Gregorian Reform to be applied.
-r Display the month in which the Gregorian Reform adjustment was applied, if no other month or year information is given. If used in
conjunction with -y, then the entire year is displayed.
-y Display a calendar for the current year.
If no parameters are specified, the current month's calendar is displayed. A single parameter specifies the year and optionally the month in
ISO format: ``cal 2007-12'' Two parameters denote the month (1 - 12) and year. Note that the century must be included in the year.
A year starts on Jan 1.
NOTES
In the USA and Great Britain the Gregorian Reformation occurred in 1752. By this time, most countries had recognized the reformation
(although a few did not recognize it until the 1900's.) Eleven days following September 2, 1752 were eliminated by the reformation, so the
calendar for that month is a bit unusual.
In view of the chaotic way the Gregorian calendar was adopted throughout the world in the years between 1582 and 1928 make sure to take into
account the date of the Gregorian Reformation in your region if you are checking a calendar for a very old date.
cal has a decent built-in list of Gregorian Reform dates and the names of the countries where the reform was adopted:
Italy Oct. 5, 1582 Denmark Feb. 19, 1700
Spain Oct. 5, 1582 Great Britain Sep. 3, 1752
Portugal Oct. 5, 1582 Sweden Feb. 18, 1753
Poland Oct. 5, 1582 Finland Feb. 18, 1753
France Dec. 12, 1582 Japan Dec. 20, 1872
Luxembourg Dec. 22, 1582 China Nov. 7, 1911
Netherlands Dec. 22, 1582 Bulgaria Apr. 1, 1916
Bavaria Oct. 6, 1583 U.S.S.R. Feb. 1, 1918
Austria Jan. 7, 1584 Serbia Jan. 19, 1919
Switzerland Jan. 12, 1584 Romania Jan. 19, 1919
Hungary Oct. 22, 1587 Greece Mar. 10, 1924
Germany Feb. 19, 1700 Turkey Dec. 19, 1925
Norway Feb. 19, 1700 Egypt Sep. 18, 1928
The country known as Great Britain can also be referred to as England since that has less letters and no spaces in it. This is meant only as
a measure of expediency, not as a possible slight to anyone involved.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
BSD
December 21, 2007 BSD