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# 1  
Old 09-20-2011
file search
hi

there is a directory structure which is being used here....and all the directory names have been listed in a file.

with grep command i need to find out all the directory names along with their full paths.....
the main purpose is that we need to find out all the different directory names and sort them and put them in a sorted manner.

like
Code:
/home/tanvi/rc/regs/power/test.g
/home/tanvi/rc/regs/power/source.g
/home/tanvi/rc/regs/frontend/test.g
/home/tanvi/rc/regs/frontend/source.g
/home/tanvi/rc/regs/frontend/my.g
/home/tanvi/rc/regs/power/power.g
/home/tanvi/rc/regs/power/my.g
/home/tanvi/rc/regs/business/my.g
/home/tanvi/rc/regs/business/power.g
/home/tanvi/rc/regs/delete/test.g
/home/tanvi/rc/regs/delete/source.g
/home/tanvi/rc/regs/power/tanvi.g
/home/tanvi/rc/regs/frontend/power.g
/home/tanvi/rc/regs/power/test.g
/home/tanvi/rc/regs/business/my.g

this is the file structure.....


thanks
kullu
Last edited by vbe; 09-20-2011 at 01:08 PM.. Reason: code tags please...
# 2  
Old 09-20-2011
Code:
# use the input file you have above == inputfilename
while read fname
do
echo "$(basename $fname):$fname"
done < inputfilename | sort | awk -F':' '{print $2}' > newoutputfilename

newoutputfile name is sorted by directory name.
# 3  
Old 09-20-2011
Quote:
Originally Posted by jim mcnamara
Code:
# use the input file you have above == inputfilename
while read fname
do
echo "$(basename $fname):$fname"
done < inputfilename | sort | awk -F':' '{print $2}' > newoutputfilename

newoutputfile name is sorted by directory name.
I did not understand the OP's problem statement, so I'm also not clear on how you interpreted it. However, I suspect that your solution may not be what you intend.

That sort is treating the colon as just another character on the line. In certain situations, this could yield improperly sorted output.

A pathological example:
Code:
foo:bar
foo0:bar

Since in the C/POSIX locale's collation sequence ":" appears after digits (and some other punctuation), sort will place foo0 before foo:. If the intent is to sort on the first field, -t: -k1,1 should be used.

But, as I said at the start, I did not truly understand the problem statement so I could very well have misunderstood your solution.

Regards,
Alister
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