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Script to find the string contain in which file 1000 files.

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# 1  
Old 09-08-2011
Computer Script to find the string contain in which file 1000 files.
Hi Greetings
i have 1000 files (xmlfiles) and i need to find which file contain the string over 1000 file
all file end with txt
i tried with
Code:
grep -c "string" *.txt

i am getting an error
Code:
-bash: /bin/egrep: Argument list too long

i have put an script like below
Code:
#!/bin/bash
for line in `cat flist`
do
     a=" grep -c "1024" $line "
     if [ a = 1 ]
     then
          echo "$line"
     fi
done

i do whats wrong with my code, Kindly guide any one for my reuirement

Regards
Venikathir

Moderator's Comments:
Mod Comment Please use [code] and [/code] tags when posting code, data or logs etc. to preserve formatting and enhance readability, thanks.
Last edited by venikathir; 09-08-2011 at 10:17 AM.. Reason: code tags, see PM
# 2  
Old 09-08-2011
You need xargs:
Code:
find . -name \*.txt | xargs grep -c "string"

# 3  
Old 09-08-2011
this one is working
its giving all files with 0 and 1
i want to list only if the string contain files is there any other way to
# 4  
Old 09-08-2011
grep -c is count lines, grep -l is list files. See man grep.
# 5  
Old 09-08-2011
your original cmd works fine here:
Code:
grep -c "string" *.txt

did test in this way:
Code:
echo "one">1.txt
touch {2..1000}.txt

# 6  
Old 09-08-2011
Quote:
Originally Posted by sk1418
your original cmd works fine here
ARG_MAX varies.

Regards,
Alister
# 7  
Old 09-08-2011
This will do it:
Code:
#!/usr/bin/ksh
for mFName in *.txt; do
  mRC=$(grep -c 'string' ${mFName})
  if [[ "${mRC}" != "0" ]]; then
    echo "Found string in <${mFName}>"
  fi
done
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