Shell Programming and Scripting

Now I find the no. of files and display the count. How can I display the maching filenames in display?? :S

---------- Post updated at 02:21 PM ---------- Previous update was at 01:40 PM ----------

Can someone pls help me printing the filenames that match the search criteria?

you want to display the file names along with the count,or you only want the matching file names

if you only want the matching file names then this is enough

Code:

ls | grep 'XX_ID*'

Thanks. Yes this was what i was trying to do. Now i have done picking up the filenames and renaming all of them in a loop.

Code:

i=0
for file in `ls |grep "$filename"`
do 
echo "$file"
echo $i
i=`expr $i + 1`
mv /var/tmp/akk2/${file} /var/tmp/akk2/${file}_${i}
done

Folks

I have a very quick question. Is there any way that I can list out all the common files with the directory name. Say for example

/home has test1 test2 test3 directories
where test1 has the files named "ABC" "DEF"
test2 has the files named "EFG" "ABC"
test3 has the files named " BC"

For this i have a common file ABC which is present in test1 and test2 directories. Instead of searching each and every directory, i need to get those 2 files to be displayed with the directory name at the root directory itself. Can someone help me out in this regard.

Any help wud be greatly appreciated. Thanks