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How to add each entry in an unix file?

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# 1  
Old 06-29-2011
How to add each entry in an unix file?
Hi,

I've a data file having entries like this-
Code:
$ cat BDWL.out
19571
349484
18963
349568
20180
351389
20372
350253

Now I want to add each entry and produce the final sum =1479780 as output.

How can I do that using unix shell scripting?? using loop or sed/awk ??

Thanks,
Naresh
Last edited by Franklin52; 06-29-2011 at 08:43 AM.. Reason: Please use code tags for code and data samples, thank you
# 2  
Old 06-29-2011
Code:
python -c 'print sum(('`cat testfile|tr '\n' ','`'))'

Smilie
# 3  
Old 06-29-2011
Thanks for the reply. Yes, this code is working... But isn't there any other way without using this option- python ? Simply using unix shell script, for/while loop or sed/awk ?

Thanks,
Naresh
# 4  
Old 06-29-2011
Code:
 awk '{s+=$1} END {print s}' BDWL.out

Jean-Pierre.
# 5  
Old 06-29-2011
Great. Thank you very muchhhhhhhhhhhh. :-)
# 6  
Old 06-29-2011
Awk is faster, but if you like to use shell loop
Code:
s=0
while read line
do
       s=$((s+line))
done < BDWL.out
echo $s

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