Shell Programming and Scripting

How do I find a duplicate files in two directories:

scenerio:

dirA:
file1
file2
file3

dirB:
file1
file4
file5
file6

file1 is residing at both locations while should be only at dirA.

ll /test/dirA | cut -c 59-80 > /test/dirA/files_at_dira
ll /test/dirB | cut -c 59-80 > /test/dirB/files_at_dirb

for file in /test/dirA/files_at_dira
do
grep $file /test/dirB/files_at_dirb
if $? = 0
then
echo "duplicate file $file found at /test/dirB/"
rm -i $file /test/dirB/
else
"duplicate file not found"
fi
done

Can some one please help on this.

Thank you in advance.
Ghazi

Try the dircmp command. Type "man dircmp".

Thanks for your reply but I wanted to set up some kind of
automated script via cron which makes the two dir in sync on regular basis.

dircmp displays dirA and dirB in tabulated form.
I tried with both -d option but does not help.

Which is supposed to get removed A or B? Try something like:

Code:

cd /B
for file in * ; do
     [[ -f  /A/$file ]] && rm $file
done

This is ksh code.

rm -i is interactive. You can't do that reasonably in a cron job. And your rm looks like you want to remove a file and some other whole directory. ???

I modified yr script ...


Pass params on the command line ... and modify the script depend on yr case ...

I have done some change and it is working for me. I going to modify it further to meet my needs.

LOG=/test/temp/DUP_CHECK.`date '+%Y%m%d%H%M%S'`

file_1=$1
file_2=$2

for file1 in `cat $1`
do
grep $file1 $2
if test $? -eq 0
then
echo "duplicate file $file1 found at $2 " >> $LOG 2>&1
else
echo "duplicate file not found" >> $LOG 2>&1
fi
done


Thanks for your help.
Ghazi


I appreciate your help.