Source Command


 
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# 1  
Old 05-03-2011
Source Command

Hello,

I have created a script that changes directories but in order for it to work I always need to invoke a source ./script

Here is a copy of my script.. if I do not invoke "source ./script" the change directory command does not work.

Any ideas?

//

The script is pretty basic
Code:
#!/usr/bin/bash
SYSLOG=/home/xxx
clear
echo ""
echo "Launch script using (Source ./team_d_menu)"
echo -e "\nTeam D Rules Menu\n"

echo "a Go to Syslog Rules"
echo "b Restart Syslog"
echo "c Copy DATA to NCOLOG"
echo "d Tail Syslog.log (Code Check)"
echo "e Restart SYSLOG Probe"

echo -e

echo -n "Enter a,b,c,d,e:"

read answer

echo

#
case "$answer" in

        a)
        cd $SYSLOG
        ;;

        b)
        ;;

        c)
        ;;

        d)
        ;;

        e)
        ;;

        *)
                echo "no selection"
esac


Last edited by Scott; 05-03-2011 at 07:29 PM.. Reason: Code tags...
# 2  
Old 05-04-2011
it works. you can add the ls after cd command to prove it.
Code:
        a)
        cd $SYSLOG
        ls
        ;;

ls will list the files under /home/xxx, not in your current folder
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