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excuting the following code

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# 1  
Old 04-01-2011
excuting the following code
hi
i am trying the below code for the following

Code:
 
|_
|  |_
|  |_ |_
|  |_ |_ |_
|  |_ |_ |_ |_

and for this code also

Code:
*
* *
* * *
* * * *
* * * * *

Code:
!/bin/bash
#i = "*"
#read i
for((i="*";i<=5;i++))
do
 for((j="*";j<=$i;j++))
  do
   echo -n $i"*"
 done
 echo "*"
done



where am i going wrong????
Last edited by joeyg; 04-01-2011 at 03:35 PM.. Reason: Please wrap data and programs with CodeTags
# 2  
Old 04-01-2011
Without checking syntax, I do not think you mean to start counting at "*" with your i & j variables. Perhaps starting to count at 1 would work better.
(Not sure how you i++ an asterisk.)
# 3  
Old 04-01-2011
The i and j variable must be numeric only. It's not obvious why you are using a double loop.

Code:
$ cat x1
#!/bin/bash
line=""
for((i=0;i<=5;i++)); do
        line="$line|_"
        echo "$line"
done
$ ./x1
|_
|_|_
|_|_|_
|_|_|_|_
|_|_|_|_|_
|_|_|_|_|_|_
$

This User Gave Thanks to Perderabo For This Post:
kullu
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