Shell Programming and Scripting

Hi all,

before posting this questions i have looked up and found similar cases as the one i have but none of them had the answer i was lookink for.

i have the next two commands (with their corresponding output)

Code:

e1=$(grep KCAL input.OUT | sed 's/          FINAL HEAT OF FORMATION =        //g' | sed 's/ KCAL/0/g')
printf "%s\n" "Energia para configuracion 1= $e1 KCAL"
Energia para configuracion 1= -16.888990 KCAL

Code:

e2=$(grep KCAL input.OUT | sed 's/          FINAL HEAT OF FORMATION =        //g' | sed 's/ KCAL/0/g')
printf "%s\n" "Energia para configuracion 2= $e2 KCAL"
Energia para configuracion 2= -25.709240 KCAL

As you can see these two commands are correct, so $e1 and $e2 are actually numbers.

The problem is when i do the following:

Code:

scale="scale=6"
de=$(echo "$scale;$e2-$e1" | bc -l)
echo $de

i get the next error:

Code:

(standard_in) 1: syntax error

what i have found is that the sed output (or grep, certainly i'm not sure which of the two) is not compatible for a bc calculation; but i didn't find a solution for this. Perhaps the problem is not the one i think it should be.

Any suggestions would be apreciated. (Sorry for my english)

Code:

de=$(echo "$scale;($e2)-($e1)" | bc -l)

WOW, that was pretty simple!

Thank you very much!

---------- Post updated at 03:02 PM ---------- Previous update was at 03:02 PM ----------

WOW, that was pretty simple!

Thank you very much!