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how do you to add numbers incrementally?

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# 1  
Old 11-01-2004
how do you to add numbers incrementally?
I've refined the filesystem size using awk and directed to a file name.

eg, here's the content in a file called "numbers"

$cat numbers
345
543
23423456
44435
546
.
.

how do you write a script to all these numbers to get the total?

thanks a lot.
# 2  
Old 11-01-2004
sum=0
for i in `cat numbers`
do
((sum=sum+$i))
done

echo "sum=$sum"
# 3  
Old 11-01-2004
bhargav,
thanks for a quick response. that did it.
# 4  
Old 11-01-2004
Also possible in awk...

awk '{m+=$1}END{print m}' numbers
# 5  
Old 11-09-2004
Hi there,

does someone knows about such a simple method to add hexadecimal numbers using awk ?

thanks,
homefp
# 6  
Old 11-09-2004
To sum two numbers....

With GNU awk, yes
Code:
$ awk 'BEGIN { printf "%x\n", 0xa + 0x2 }'
c

Prefix your hexadecimal values with 0x (or 0X), and use %x as a format specifier.


You also could use ksh
Code:
$ var_a="16#a"
$ var_b="16#2"
$ typeset -i16 var_c
$ ((var_c=var_a+var_b))
$ echo $var_c
16#c

Which is what you'd expect in base 16 (A + 2 = C).
# 7  
Old 11-09-2004
thanks,

how then would I replace the following :

awk '{m+=$1}END{print m}' numbers

with hexa numbers in $1 field ?

I need to have it as simple as possible in a shell script.
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