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# 8  
Old 12-28-2010
OK, so here you have only one requirement. In my previous post, I was talking about many more processing on crontab files mentioned in post #1.
if -i switch is supported:
Code:
sed -i 's!.*\/dev1\/scripts\/.*!#&!' cronfile.txt

If not:
Code:
sed 's!.*\/dev1\/scripts\/.*!#&!' cronfile.txt > temp; mv temp cronfile.txt

Last edited by anurag.singh; 12-28-2010 at 04:16 PM..
These 2 Users Gave Thanks to anurag.singh For This Post:
einsteinBrain svajhala
# 9  
Old 12-28-2010
OK. Great.

Can I use a variable which contains the path in it and use it in sed statement, rather than hard coding it?

for example,

Code:
export script_path=/dev1/scripts

Code:
$echo $script_path
/dev1/scripts

# 10  
Old 12-28-2010
Code:
sed "s|.*${script_path}.*|#&|" cronfile.txt > cronfile.new

Last edited by Scrutinizer; 12-28-2010 at 04:50 PM..
This User Gave Thanks to Scrutinizer For This Post:
einsteinBrain
# 11  
Old 12-28-2010
Quote:
Originally Posted by anurag.singh
To do some action on some specific lines, some pattern has to be identified for them. Say we want to comment all lines where "pc" is a substring of script name, then:
Code:
sed '/pc/ s!.*!#&!' cron_file

Still your overall requirements are not clear. Input file is known but you need multiple processing on that file. You need to mention everything you need to do on that file along with complete expected output.
Hi Anurag,

I am a newbie to this scripting. can you please explain me what "s!.*!#&!" does in the code you have written above.

i really appreciate your solutions to users queries.
Thanks in advance.

---------- Post updated at 03:47 PM ---------- Previous update was at 03:46 PM ----------

Quote:
Originally Posted by Scrutinizer
Code:
sed "s|.*${script_path}.*|#&|" cronfile.txt


can you please explain this. I am a newbie
# 12  
Old 12-28-2010
@Scrutinizer - Your solution commenting out all the entries in cron file which i do not want to do. I want to comment only the entries matching the value in $script_path which is /dev1/scripts/


Code:
#!/bin/ksh

. /home/.profile

crontab -l > temp

sed "s|.*${script_path}.*|#&|" temp > cronfile.txt

Code:
ussbazudb129[infrep9d]:/info_d16/PC_Intg_Svc_01/Scripts/Admin_Utils>cat cronfile.txt

Code:
#0-59 * * * * /dev1/scripts/check_proc.sh >> /tmp/check_infa_proc_cron.log 2>&1
#0-59 * * * * /dev1/scripts/check_cores.sh >> /tmp/check_cores_cron.log 2>&1
#0-59 * * * * /dev1/scripts/check_repo_conn.sh >> /tmp/check_repo_conn_cron.log 2>&1
#0-59 * * * * /dev1/scripts/check_num_proc.sh >> /tmp/check_num_proc_cron.log 2>&1
#0-59 * * * * /dev1/scripts/check_pc.ksh >> /tmp/check_powercenter_cron.log 2>&1
#0-59 * * * 7 /dev1/admin/scripts/check_users.ksh /tmp/check_users.log 2>&1

# 13  
Old 12-28-2010
@svajhala
Don't forget to set the variable $script_path first..

---------- Post updated at 22:02 ---------- Previous update was at 21:51 ----------

Quote:
Originally Posted by einsteinBrain
can you please explain this. I am a newbie
Sure, with the substitution operator s you can use any character (except backslash and newline ) as a delimiter so instead of / I used | .
The pattern to match is .*${script_path}.* which matches the whole line if the contents of $script_path are part of the line. If the latter is the case then it gets replaced by a # , followed by the line that was matched ( & ) . Everything is in double quotes so that variables get expanded by the shell.

I hope I explained it clearly?
Last edited by Scrutinizer; 12-28-2010 at 05:08 PM..
These 2 Users Gave Thanks to Scrutinizer For This Post:
einsteinBrain svajhala
# 14  
Old 12-28-2010
Yes I am doing that prior to the execution of sed statement.

Code:
. /home/.profile

Code:
$cat .profile
export scripts_path=/dev1/scripts
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