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# 1  
Old 12-27-2010
sed selective printing
Hi,

I have an xml file having serveral smiliar lines as below


Code:
<INPUT VAR1 ="" DATATYPE ="number(p,s)" VAR2 ="" VAR3 ="3" VAR4="0" VAR5 ="ELEMITEM" VAR6 ="NO" VAR7 ="NOT A KEY" VAR8 ="17" LEVEL ="0" NAME ="UNIX" NULLABLE ="NOTNULL" OCCURS ="0" OFFSET ="19" PHYSICALLENGTH ="15" PHYSICALOFFSET ="29" PICTURETEXT ="" PRECISION ="15" SCALE ="0" USAGE_FLAGS =""/>

Now if I want to print only the lines having the pattern as NAME= "UNIX" from the xml file then how can I do that?

I know that we can use

Code:
 
sed -n '/regex/p'

for this purpose. But it works if regex=UNIX but what I want is to search for regex=NAME ="UNIX". Something like this
Code:
sed -n '/NAME ="UNIX"/p'

Can someone please suggest?
-dips
# 2  
Old 12-27-2010
Code:
grep "NAME =\"UNIX\"" file

R0H0N
# 3  
Old 12-27-2010
try
Code:
sed -n '/NAME \="UNIX"/p'

# 4  
Old 12-27-2010
Thanks both of you!
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