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Shell Programming and Scripting

Counting

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# 1  
Old 10-30-2010
Counting
Hi,
The following output shows how many pmon process are started by users named : oracle or yoavb
Code:
[/home/yoavb]$ ps -ef |grep pmon |grep -v grep |grep -v ipmon
  oracle 11268     1  0  Sep  2  ?        36:00 ora_pmon_qerp
  oracle 17496     1  0  Oct 11  ?         8:58 ora_pmon_bcv
  oracle 15081     1  0  Sep  6  ?        19:08 ora_pmon_trn
  oracle  5310     1  0  Oct 14  ?         7:19 ora_pmon_bildev
  yoavb  25467     1  0  Oct 24  ?         2:44 ora_pmon_qa2

I Would like to know, how to count (wc -l) how many process DID NOT started by user ORACLE
Thanks
Last edited by Scott; 10-30-2010 at 08:43 PM.. Reason: Code tags
# 2  
Old 10-30-2010
try:
Code:
grep '_[p]mon_' | grep -v "^oracle" | wc -l

Code:
sed '/_[p]mon_/!d;/^oracle/d' | wc -l

Code:
awk '/_[p]mon_/ && $1!="oracle"' | wc -l

Code:
awk '/_[p]mon_/ && $1!="oracle"{i++} END{print i}'

# 3  
Old 10-30-2010
you dont have to use `wc -l` Smilie
Code:
# ps -ef | sed -n '/^[^oracle].*[^a-z*]pmon/p'|sed -n '$='

# 4  
Old 10-30-2010
Code:
ps -ef |awk '$1!="oracle"&&!/_[p]mon_/ ' |wc -l

ps -ef |awk '$1!="oracle"&&!/_[p]mon_/ {sum++}END{print sum}'

# 5  
Old 10-31-2010
Quote:
Originally Posted by ygemici
you dont have to use `wc -l` Smilie
Code:
# ps -ef | sed -n '/^[^oracle].*[^a-z*]pmon/p'|sed -n '$='

You do not have to use wc -l, but sed is much less efficient. See:
https://www.unix.com/shell-programmin...wc-l-2.html#13

Quote:
Originally Posted by rdcwayx
Code:
ps -ef |awk '$1!="oracle"&&!/_[p]mon_/ ' |wc -l

ps -ef |awk '$1!="oracle"&&!/_[p]mon_/ {sum++}END{print sum}'

That should be &&/_[p]mon_/, no?
# 6  
Old 10-31-2010
MySQL
Quote:
Originally Posted by Scrutinizer
You do not have to use wc -l, but sed is much less efficient. See:
https://www.unix.com/shell-programmin...wc-l-2.html#13
yes i already save this in my notes thanks a a lot of for usefull infos Smilie Smilie
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