10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi All,
I have my data like below
"1","abc,db","hac,aron","4","5"
Now I need to extract 1,2,4th columns
Output should be like
"1",abc,db","4"
Am trying to use cut command but not able to get the results.
Thanks in advance. (4 Replies)
Discussion started by: weknowd
4 Replies
2. Shell Programming and Scripting
Hi All,
I'm stuck-up in finding a way to skip the delimiter which come within double quotes using awk or any other better option. can someone please help me out.
Below are the details:
Delimited: |
Sample data: 742433154|"SYN|THESIS MED CHEM PTY.... (2 Replies)
Discussion started by: BrahmaNaiduA
2 Replies
3. Shell Programming and Scripting
Hi ,
Please suggest me how do I use : (colon and one space) as a delimiter in awk
Best regards,
Vishal (2 Replies)
Discussion started by: Vishal_dba
2 Replies
4. UNIX for Dummies Questions & Answers
Hi
I am trying to parse the following lines and has to use * (asterisk) as the delimiter.
These lines are in a file, for example tmp.txt and I am using a while loop
tmp.txt:
14-OCT-2012 06:38:59 *... (1 Reply)
Discussion started by: newbie_01
1 Replies
5. Shell Programming and Scripting
# echo "size(JFJF" | awk -F"size(" '{print $1}'
awk: fatal: Unmatched ( or \(: /size(/
the delimiter is "size(" but i'm not sure if awk is the best tool to use to specify it.
i have tried:
# echo "size(JFJF" | awk -F"size\(" '{print $1}'
awk: warning: escape sequence `\(' treated as... (1 Reply)
Discussion started by: SkySmart
1 Replies
6. UNIX for Dummies Questions & Answers
Hi
I have a asterisk (*) delimited file and there are some fields which contain data having asterisk , now i want to double quote the fileds which contain data with asterisk
Ex:
input file
ID*NAME*EMAIL
1*BILL*BILL@AOL.com
2*J*OY*JOY@msn.com
in the 2nd record JOY has a asterisk value in... (11 Replies)
Discussion started by: halmstad
11 Replies
7. Shell Programming and Scripting
I'm trying to extract a column from a csv file with either cut or awk but some of the fields contain comma with them:
"Field1","Field2, additional info","Field3",...,"Field17",...
If I want to extract column 3 and use comma as the delimiter, I'll actually get the additional info bit but not... (4 Replies)
Discussion started by: ivpz
4 Replies
8. Shell Programming and Scripting
I have several hundred files that look like this:
ABB110405110000.rawfma8
AAB110405110001.rawhr32
If I use the statement ls | awk '{x=$0;gsub("","",x)
I see that all characters other than 0-9 are eliminated but how do I eliminate all characters including numbers after the "."
In my mind I... (1 Reply)
Discussion started by: rdburg
1 Replies
9. Shell Programming and Scripting
Hi,
I'm trying to insert double quotes right after the third delimiter in a file. Delimiter is ^Z.
For example:
Input:
Oct ^Z 1234 ^Z John ^Z Hello!"
Desired Output:
Oct ^Z 1234 ^Z John ^Z "Hello!"
Any ideas? (1 Reply)
Discussion started by: kangaroo
1 Replies
10. UNIX for Advanced & Expert Users
Hi All,
Can the cut command have double character delimiter?
If yes, how can we use it.
if my data file contains :
apple || mango || grapes
i used
cut -f1 -d"||" filename
but got an error.
Plz help....
Thanks. (1 Reply)
Discussion started by: AshishK
1 Replies
IGAWK(1) Utility Commands IGAWK(1)
NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO
gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)