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# 8  
Old 08-31-2010
for the first result, but perhaps better:

Code:
cat file | awk 'NR>3' | awk '{print $2, $4, $5, $7, $8}' | tr ',' ' '

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ronaldomitsuo
# 9  
Old 08-31-2010
Code:
$ awk -F '[ ,\t]*' 'NR>3{print $2,$4,$5,$6,$8,$9,$10}' infile
001 34 31 03 49 18 04
002 34 12 40 49 56 21
003 33 53 45 50 35 37
004 33 35 05 51 10 99
005 33 28 40 51 24 18

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ronaldomitsuo
# 10  
Old 09-02-2010
Quote:
Originally Posted by ronaldomitsuo
hi,

[..]

Code:
awk -F '[ ,\t]*' 'NR>3{print $2,$4,$5,$6,$8,$9,$10}' infile

it worked and a i liked your solution! but I didn't understand it perfectly. could you explain what the contents of '-F '[ ,\t]*' 'NR>3{program text}' does?

thanks for help me!
Hi ronaldomitsuo,

[ ,\t]* means use a space, comma and tab character as field separator and treat consecutive occurrences as one (*). Using these separators the desired fields now become $2,$4,$5,$6,$8,$9 and $10. Print lines only if their line number is 4 or higher (NR>3). (fields are printed using space as separator, which is the default).

Does this give you the answer you need?

S.
This User Gave Thanks to Scrutinizer For This Post:
ronaldomitsuo
# 11  
Old 09-02-2010
Thank you very much, Scrutinizer!

Very clear, i understood!
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