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Help me with awk and grep script

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# 1  
Old 04-07-2010
Help me with awk and grep script
Code:
#!/bin/sh
PRINTF=/usr/bin/printf

$PRINTF "Enter a UserID\n"
read USERID

for USERID in `cat passwd | awk -F : '{print $1}'`
do
    USERHOME=`grep ^$/qianxin/ passwd | awk -F : '{print $6}'`
    USERSHELL=`grep ^$/qianxin/ passwd | awk -F : '{print $7}'`

$PRINTF "$USERID\n"
$PRINTF "$USERHOME\n"
$PRINTF "$USERSHELL\n"

done

Hi all, I got execution problem with this script, can someone please help me fix it?

In this script, first promote the user enter a valid ID, then if the ID is in the first field of a passwd file, system will print out the sixth and seventh filed. The type of a passwd file is in this way:
root:89898:93434:root...:dfdfd:ererer:ferer:

thx a lot!
# 2  
Old 04-07-2010
What is the error you are getting?

Try using the full path for the password file if you are not executing from that directory.


Also not sure why you are using this

Code:
grep ^$/....


If your requirement is to grep the user_id just entered remove the forloop

Code:
#!/bin/sh
PRINTF=/usr/bin/printf

$PRINTF "Enter a UserID\n"
read USERID

USERHOME=`grep "$USERID" /etc/passwd | awk -F : '{print $6}'`
USERSHELL=`grep "$USERID" /etc/passwd | awk -F : '{print $7}'`

$PRINTF "$USERID\n"
$PRINTF "$USERHOME\n"
$PRINTF "$USERSHELL\n"

HTH,
PL
Last edited by daptal; 04-07-2010 at 01:05 AM..
# 3  
Old 04-07-2010
Thx for u help.

BTW, is there any files that map userid to home directory and other information?
# 4  
Old 04-09-2010
One (of many) unix programs which give this information is "finger".

Code:
finger -m username

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