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Convert date with awk

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# 1  
Old 03-25-2010
Convert date with awk
Hi all,

I'm fighting with awk because I didn't find any way with other commands Smilie

I need to convert a date from format A to format B :
format A : "YYYY MM DD"
format B : "DD-MON-YYYY"

Exemple : "2010 3 25" => "25-MAR-2010"

My main difficulty is to convert the month with something like that :
Code:
split("JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC", month, " ")

Help me please...
# 2  
Old 03-25-2010
Code:
$ echo '2010 3 25' | nawk 'BEGIN{split("JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC", month, " ")} {print $3,month[$2],$1}' OFS=-
25-MAR-2010

# 3  
Old 03-25-2010
Perfect !

month[$2] of course Smilie

Many thanks
# 4  
Old 04-05-2010
How do I go about doing the reverse of this? Say I have a date in the

format A:
APR 02, 2010

and want it converted to

format B:
04/02/2010

??

Thanks,
Bharath
# 5  
Old 04-05-2010
Code:
echo 'APR 02, 2010' | nawk 'BEGIN{FS=FS "|,";split("JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC", month, " ");while(++i in month) m[month[i]]=i} {printf("%02d%c%02d%c%d\n", m[$1],OFS,$2,OFS,$NF)}' OFS='/'

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