pipe result from grep


 
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# 1  
Old 03-17-2010
pipe result from grep

Trying to create a command line script to look for all files matching a pattern, grep for a specific value in each file, and write out the filename long list. It's possible the filename won't containe the value.

{
echo “Running....”
for fname in 811_Intermediate_File_*
do
grep -l "4400276302" $fname| <--problem occurs with grep.
while read $fname;do
echo $fname
ls -l $fname
done
done
}

Complete rewrites are accepted. Smilie
# 2  
Old 03-17-2010
Code:
ls -l $(grep -l "4400276302" 811_Intermediate_File_*)

try that.
# 3  
Old 03-17-2010
By using the 'find' command you can find files even in sub directories
Code:
ls -l $(find . -name "811_Intermediate_File_*" -exec grep -l 4400276302 {} \;)

# 4  
Old 03-18-2010
Quote:
Originally Posted by ldapswandog
By using the 'find' command you can find files even in sub directories
Code:
ls -l $(find . -name "811_Intermediate_File_*" -exec grep -l 4400276302 {} \;)

I gained a lot by these examples. I would've never thought to do it this way, or even realized I could.

Thanks !
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