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Find the next day from 20100303 (YYYYMMDD format)

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Top Forums Shell Programming and Scripting Find the next day from 20100303 (YYYYMMDD format)
# 8  
Old 03-06-2010
Actually $0 represents the first command line argument. This will be usually a script name. $1 will be next argument and so on....
# 9  
Old 03-06-2010
Ok...
but given arguments may be unordered by such kind of users ,in that situation how can v handle?
# 10  
Old 03-06-2010
You need to compare each and every argument by for loop and if condition.
# 11  
Old 03-06-2010
You can get every thing about date in here...

https://www.unix.com/answers-frequent...rithmetic.html
# 12  
Old 03-06-2010
As stated above, this FAQ will tell you what you need for more complex date and date arithmetic: https://www.unix.com/answers-frequent...rithmetic.html

For this specific problem, you can just use the date command.

If you have the GNU version of date, just use:

Code:
date -d "yesterday" "+%Y%m%d"

If you have BSD, POSIX, Solaris version of date, here is a simple shell script that will do it.

Code:
#!/bin/bash

#call with (basename) 'YYYYMMDD' [+-deltadays]

#there is no error checking, use at your own use...

if [ ! -n "$1" ]
then
  echo "Usage: $(basename $0) YYYYMMDD [+-days]"
  exit $E_BADARGS
fi  

if [ ! -n "$2" ]
then
  	deltadays=-1
  else
	deltadays=$2
fi  


epoch=$(date -j -f "%Y%m%d" $1 "+%s")

(( deltadays *= 60*60*24 ))
(( epoch += deltadays )) 

newday=$(date -j -f "%s" $epoch "+%Y%m%d")

echo $newday

# 13  
Old 03-15-2010
THANKS FOR REPLAY...AND I GOT SOME IDEA FOR MY REQUIREMENT>>>

i need one more help....

if i have a string like aaaaa,bbbbb,ccccc,aaaaa

How to to split the string and check howmany times aaaaa will be in that string?
# 14  
Old 03-15-2010
Quote:
Originally Posted by karthinvk
THANKS FOR REPLAY...AND I GOT SOME IDEA FOR MY REQUIREMENT>>>

i need one more help....

if i have a string like aaaaa,bbbbb,ccccc,aaaaa

How to to split the string and check howmany times aaaaa will be in that string?
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