Shell Programming and Scripting

What F_NAME stands for? Can you give us some input?

Hi.

It returns the value of $F_NAME without the last few characters (that being however many dots you have there).

Code:

$ echo $F_NAME
123456789

$ echo $F_NAME | sed 's/\(.*\).../\1/'
123456

In this case, it's really the same as

Code:

echo $F_NAME | sed 's/...$//'

Thanks a lot for the quick reply.

EAGL€ - Please find the input.

F_NAME= Y_FISCAL20100217090702.dat

INput: echo Y_FISCAL20100217090702.dat | sed 's/\(.*\)................../\1/'
Output: Y_FISCAL

Scottn: You are right. It is excluding last few character based on the number of dots. If it is not too much to ask for. Can you please explain the need of \(.*\) and /\1 in the statement. I have a requirement to strip off few characters from the back and few character from the starting. I would like to have a output like: FISCAL (after stripping first two characters). Please advice what changes I need to make to this statement.

Hi Sid,

Yes Scottn gave you the exact solution. Besides If you like to find out more about Multigrouping in SED then you can have a look at this page, i found some good examples there:

Unix Sed Tutorial: Advanced Sed Substitution Examples (link removed)

regards

Thanks for the link buddy. I believe I should be able to move on from there.

Code:

echo "Y_FISCAL20100217090702.dat" | sed 's/\(._\)\(.*\)................../\2/'

gives only FISCAL

or you can simply use "." instead of underscore

Code:

echo "Y_FISCAL20100217090702.dat" | sed 's/\(..\)\(.*\)................../\2/'