Shell Programming and Scripting

Okay, probably an easy solution, but I've given up. I want to set a variable with a variable and print it in PHP. I just can't get the syntax right. As an example:

Code:

$place["t"] = "T";

$norm_t = array("4","7");

I want to use this in a for-loop. How do I echo the first number of the norm_t array???

I've tried:

Code:

foreach ($place as $id => $name)  {
#so id is now t.  

echo "$norm_{$id}[0]"  
}

# This doesn't seem to work. I want to echo the variable $norm_t using the "id" variable. I'm new to php and can think of how this is done in other languages, but the proper syntax for php eludes me.

Dave

I don't think you can construct the names of a variable in PHP by treating the variable name as a string and concatenating two variables names together as you are trying to do. One way to do it in PHP would be to define norm_t as a two dimensional array.

Note: I could be wrong, but I have not seen this (as you are trying to do) and I look at a lot of PHP code every week!

PS: You are missing a ";" in your code (syntax error)

I think your right. I've search through all sorts of online documentation, and have found nothing. No big deal. Time to find a better route.

If you use a two dimensional array it is easy...

I have not used two dimensional arrays before. I will look into it. thanks,

Dave