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Conversion of '|' delimiter

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Top Forums Shell Programming and Scripting Conversion of '|' delimiter
# 8  
Old 02-01-2010
Quote:
Originally Posted by ssachins
Code:
#!/usr/bin/ksh
FileName=INPUT_FILE.txt

if [[ -e $FileName ]]; then
while read line
  do
    awk -F |  '{for( i = 1;i <= NF;++i)
      if( i % 2 == 0 ) printf("%s\n",$i) 
    else
      printf("%s|",$i) ; }'
  done < $FileName
else
   echo "File $FileName  does not exists"
fi

Thank you in advance.
Fix your code.

Code:
#!/usr/bin/ksh
FileName=INPUT_FILE.txt

if [[ -e $FileName ]]; then
  awk -F "|"  '{for( i = 1;i <= NF;++i)
      if( i % 2 == 0 ) printf("%s\n",$i)
      else
        printf("%s\t",$i) ; }{print ""}' $FileName
else
   echo "File $FileName  does not exists"
fi

# 9  
Old 02-02-2010
The above mentioned code is converting the first '|' to Tab delimited but unable to format the second '|' value to new line.

Also, I found another issue is like the input file does not contains the '|' at the end of each line hence when I execute the file using Ahmad's code, the format is getting changed from second line.

The actual data is coming like this -
Code:
NAME|ABC|LASTNAME|PQR|AGE|20|SEX|MALE
NAME|XYZ|LASTNAME|PDF|AGE|21|SEX|MALE

# 10  
Old 02-02-2010
Quote:
Originally Posted by ssachins
The above mentioned code is converting the first '|' to Tab delimited but unable to format the second '|' value to new line.

Also, I found another issue is like the input file does not contains the '|' at the end of each line hence when I execute the file using Ahmad's code, the format is getting changed from second line.

The actual data is coming like this -
Code:
NAME|ABC|LASTNAME|PQR|AGE|20|SEX|MALE
NAME|XYZ|LASTNAME|PDF|AGE|21|SEX|MALE

My code are not changed for your new INPUT_FILE.txt, but still get correct result.

Code:
$ cat INPUT_FILE.txt
NAME|ABC|LASTNAME|PQR|AGE|20|SEX|MALE
NAME|XYZ|LASTNAME|PDF|AGE|21|SEX|MALE

$ cat ssachins.sh
#!/usr/bin/ksh
FileName=INPUT_FILE.txt

if [[ -e $FileName ]]; then
  awk -F "|"  '{for( i = 1;i <= NF;++i)
      if( i % 2 == 0 ) printf("%s\n",$i)
      else
        printf("%s\t",$i) ; }{print ""}' $FileName
else
   echo "File $FileName  does not exists"
fi

$ ./ssachins.sh
NAME    ABC
LASTNAME        PQR
AGE     20
SEX     MALE

NAME    XYZ
LASTNAME        PDF
AGE     21
SEX     MALE

# 11  
Old 02-02-2010
I tried the above code too but getting the below error -
Code:
awk: syntax error near line 1
awk: bailing out near line 1

# 12  
Old 02-02-2010
Quote:
Originally Posted by ssachins
I tried the above code too but getting the below error -
Code:
awk: syntax error near line 1
awk: bailing out near line 1

Use nawk or /usr/xpg4/bin/awk on Solaris.
# 13  
Old 02-08-2010
It's working now.
Thank you all.
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