Shell Programming and Scripting

Gurus

I am trying to capture all the data in /etc/group file in a CSV ,thru a fingerprinting engine.

For hosts having ,unique group names and Ids ,following code works fine.

Trouble starts when on a host,there are multiple groups defined with same name and id.

e.g One of my hosts has 8 groups defined with [same]name "operators" and [same] id "542".

Query1:
How can i capture all these 8 groups with following script lines?

Query2:

Code:

myHost        operators  542     jackS johnM 2009-12-01

I am getting two names in the third column (userlist).'jackS' is where first group entry ends and 'johnM' is where second or next entry begins.
How can this be avoided?

Query3:
Is it possible to define multiple groups with same name and id?

Code:

Family Name:Host etcGroup

DUP:
cat /etc/group | awk -F':' '{print $1$3}'

GroupName:
A=`cat /etc/group |awk -F':' '{if ($1$3 == "@@Host etcGroup.DUP@@" ) print $1}'|sort|uniq`
echo $A

GID:
A=`cat /etc/group |awk -F':' '{if ($1$3 == "@@Host etcGroup.DUP@@" ) print $3}'|sort|uniq`
echo $A


Userlist:
A=`cat /etc/group|awk -F':' '{if ($1$3 == "@@Host etcGroup.DUP@@" ) print $4}'|sort|uniq`

B=`echo $A|wc -w`

if [ $B = 0 ]
then
echo NULL
else
count=`echo $A| nawk -F, {'print NF'}`
i=1
while [ $i -le $count ]
do
str[$i]=`echo $A| cut -d, -f${i}`
echo "${str[$i]}"
i=`expr $i + 1`
done
fi

Regards
Abhi