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Shell Programming and Scripting

Line Number Script

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# 1  
Old 12-01-2009
Line Number Script
If i have text file how do i find the line with the nth occurance of a certain string, so in example below i want line number of 3rd occurance of COD1 which should be line 7

COD1
COD2
COD2
COD1
COD2
COD2
COD1
# 2  
Old 12-01-2009
Debian
Code:
awk '/COD1/&&++c==3&&$0=NR' infile

or:

Code:
awk '/COD1/&&++c==3{print NR}' infile

# 3  
Old 12-01-2009
How do i run this in a script and assing it to a variable.

I try something like:

numVal=`awk '/COD1/&&++c==3{print NR}' infile`

And get the following error when running script

numVal : command not found
# 4  
Old 12-01-2009
Code:
$ awk -v numVal=3 '/COD1/&&++c==numVal {print NR}' urfile
7

$ awk -v numVal=2 '/COD1/&&++c==numVal {print NR}' urfile
4

# 5  
Old 12-01-2009
This might also be interesting in some cases:
Code:
grep -nm3 COD1 infile

# 6  
Old 12-01-2009
shell
Code:
i=0
linenum=0
while read -r line
do
    linenum=$((linenum+1))
    case "$line" in
    *COD2* )
        i=$((i+1))
        [ "$i" -eq 3 ] && echo $linenum && exit        
    ;;
    esac
done <"file"

# 7  
Old 12-01-2009
Perl:

Code:
$
$ cat -n f6
     1  COD1
     2  COD2
     3  COD2
     4  COD1
     5  COD2
     6  COD2
     7  COD1
$
$ perl -lne 'if (/COD1/){$i++; print $. if $i == 3}' f6
7
$
$

tyler_durden
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