Shell Programming and Scripting

If awk is allowed

Code:

awk '/^dn/ && gsub("ou=","ou=")==3' file

Ok using a better example:

My aim is to print the rows with 3 ous and 3rd ou should not contain a comma. Following is the sample file:

# cat ou_comma_eg.ldif
So I executed
# grep -i '^dn:\(ou=[^,]\+,\)\{1\}ou=Company,ou=Personal,o=paragkalra.com' ou_comma_eg.ldif
As you can see first 2 rows were not printed as it contained a comma and last 2 rows were not printed as it has 4 ous. Hence only 3rd row was printed.

Ah! OK!

That is different than your first requirement (in your first post on this topic). Now I understand