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Shell Programming and Scripting

go to / skip in script

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# 1  
Old 11-04-2009
go to / skip in script
Hi all
I have some script like this
Code:
#!/bin/bash
mv /tmp/file1 tmp/file2
if [[ $? -eq 0 ]] ; then
  cp /tmp/filetest/ tmp/file3
     if [[ $? -eq 0 ]] then 
      echo "succes"
    else 
      echo "failed"
    fi
else   
 echo "failed"
fi

i didn't try to see if it's work, the thing is that i don't care if it's failed in phase one or two, is there any way to short this written without all this echo
somethis like this
Code:
#!/bin/bash
mv /tmp/file1 tmp/file2
if [[ $? -eq 0 ]] ; then
  cp /tmp/filetest/ tmp/file3
     if [[ $? -eq 0 ]] then 
      echo "succes"
    else 
     go to fail
    fi
else   
 go to fail
fi

fail.
echo "script failed" 
.

or any other way to short this complex script.

thank you very much
best regards
Last edited by Franklin52; 11-04-2009 at 09:38 AM.. Reason: Please use code tags!
# 2  
Old 11-04-2009
Code:
if mv /tmp/file1 tmp/file2 && cp /tmp/filetest/ tmp/file3; then
  echo success
else
  echo failed
fi

# 3  
Old 11-05-2009
Hi
thanks for the response,
According to the syntax if the first command failed
mv /tmp/file1 tmp/file2
it continue to the second command :/tmp/filetest/ tmp/file3.
this is not what i wanted, i need that if the first command, failed ,
it won't continue to the second.
any other idea ?
Best regards.
# 4  
Old 11-05-2009
Quote:
Originally Posted by naamas03
i need that if the first command, failed , it won't continue to the second..
That's what you want... that's what you got Smilie
Learn the difference between && and ||
# 5  
Old 11-05-2009
Like sanmero says this is exactly how && works... Because of efficiency the right side only gets evaluated if the left side is true. If the left side is false it does not matter what value the right side evaluates to, so it never gets evaluated.

S.
Last edited by Scrutinizer; 11-05-2009 at 11:30 AM..
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