Shell Programming and Scripting

Folks;
I'm trying to write a script to scan through a directory tree then for each file it finds, it run a command line tool, then if the results include the word "DONE", it removes the file.
In more details;
i have a Linux directory tree such as "/opt/grid/1022/store"
I'm trying to write a script going through this tree and every file it finds, it should run this command on it:

/opt/dev/chktool -getstat file_name |grep -v "DONE"

If the output include the word "DONE" then we need to remove it, if not, skip to the next one.

Any help is greatly appreciated

You may never get "DONE" because you are using grep -v.
If I understood your query properly, you probably need this...

Code:

for file_name in `find . -name 'pattern' -print`
do
   if [[ `/opt/dev/chktool -getstat $file_name |grep -c "DONE"` -gt 0 ]]; then
      #rm $file_name
   fi
done

But i don't know the file names, I need to run the tool on any file that can be in the directory tree

Try this:

Code:

for file_name in `ls /opt/grid/1022/store`
do
    if [[ ! -z `/opt/dev/chktool -getstat $file_name |grep "DONE"` ]]; then   
          rm -f ${file_name}
    fi
done

regards,
Arun.

I still see "file_name" in the if statement.
I think i didn't explain it better,
What i'm looking for is to go through the directory tree, find any file under any subdirectory then run the tool on it, if the output include the word "DONE" then remove the file, if not, leave the file alone and go to the next file and do the same thing.

I hope that makes it more clear

Did you even try the code that rakesh and I posted here?

regards,
Arun.

I did try it but i'm getting "failed to open the next directory"

How can i make it go search every directory and subdirectory for files then perform the tool on every file it find?