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sed remembering part of pattern using \1 concept

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# 8  
Old 06-17-2009
code :-

Code:
sed 's/.*\=\([0-9]*\.[0-9]*\.[0-9]*\.[0-9]*\).*/\1/g'

Also this below will work

Code:
sed 's/.*node=\([^a-zA-Z,]*\).*/\1/g'

BR
# 9  
Old 06-17-2009
Thanks to all for the replies.
The solutions given by Franklin and ahmad(second one) is most suited to me, since i need a generic expression, not something that is specific (eg. IP address only).

sed 's/.*node=\([^,*]*\).*/\1/'

Works well.

But i didn't quite get the logic of this code. Hoping to get an explanation Smilie
# 10  
Old 06-17-2009
Quote:
Originally Posted by indianjassi
Thanks to all for the replies.
The solutions given by Franklin and ahmad(second one) is most suited to me, since i need a generic expression, not something that is specific (eg. IP address only).

sed 's/.*node=\([^,*]*\).*/\1/'

Works well.

But i didn't quite get the logic of this code. Hoping to get an explanation Smilie
Explanation:-

Code:
sed '
/.*                           #means any string [numbers or char] strings (0 or   more times)
node=                      #means node=

\([^,*]*\) :-
 \(\)                        # means remember 
[^,*]                      # means not "," (0 or more times)
*                            # (repeated 0 or more times)

\1                         # means to print what he had remember

# 11  
Old 06-17-2009
Quote:
Originally Posted by indianjassi
Thanks to all for the replies.
The solutions given by Franklin and ahmad(second one) is most suited to me, since i need a generic expression, not something that is specific (eg. IP address only).

sed 's/.*node=\([^,*]*\).*/\1/'

Works well.

But i didn't quite get the logic of this code. Hoping to get an explanation Smilie
This \([^,*]*\) means: select everything in a portion after .*node= without a comma.

Regards
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