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sed remembering part of pattern using \1 concept

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# 1  
Old 06-17-2009
sed remembering part of pattern using \1 concept
I am using this concept to fetch value of IP address after node= in this line of csv text:

Code:
a="Measurement:,OutInviteResponseTime,Sessionid=1860700092328051458,node=67.178.40.168,nodeName=abcd,protocol=GK,25523000"

echo $a | sed 's/.*node=\(.*\).*/\1/'

But this outputs:
Code:
67.178.40.168,nodeName=CHCIILNQPS1_Area4_67.178.40.168,protocol=SIP,25523000

I only want output till 67.178.40.168, that is, text between node= and comma (,).

Note: I can't use AWK on this because the columns are variable in input.
# 2  
Old 06-17-2009
Try this...
Code:
echo $a | sed 's/\(.*\)node=\(.*\),nodeName\(.*\)/node=\2,/'

# 3  
Old 06-17-2009
Quote:
Originally Posted by rakeshawasthi
Try this...
Code:
echo $a | sed 's/\(.*\)node=\(.*\),nodeName\(.*\)/node=\2,/'

I want a solution that has no dependency on other columns, because as i said that my input string will have variable columns.
# 4  
Old 06-17-2009
Try a regular expression after node=, like
[0-9][0-9].[0-9]..and so on.
try first yourself.
# 5  
Old 06-17-2009
Try this:

Code:
sed 's/.*node=\([^,*]*\).*/\1/'

# 6  
Old 06-17-2009
Quote:
Originally Posted by Franklin52
Try this:

Code:
sed 's/.*node=\([^,*]*\).*/\1/'

Thanks Franklin52

Can you please explain the logic? I didn't quite understand the use of square brackets.
# 7  
Old 06-17-2009
Code:
echo "a="Measurement:,OutInviteResponseTime,Sessionid=1860700092328051458,node=67.178.40.168,nodeName=abcd ,protocol=GK,25523000"" | cut -d ',' -f 4 | cut -d '=' -f2
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