Shell Programming and Scripting

Thanks for all the reply. Not sure why my message was not publish yesterday.

Anyway, how to check if YYMM directory is exist and if not, to create before copy files according to the directory?

Once again, appreciate all your help.

Code:

[ ! -d <directory> ] && mkdir <directory>

tyler_durden

Tried on following command:
cp -p `ls -l|awk '$6 ~ /Jun/{print $9}'` path/0906 --> OK.

# cp -p `ls -l *.* | awk '$6 ~ /$mon/{print $9}'` 0906
awk: syntax error near line 1
awk: bailing out near line 1
cp: Insufficient arguments (1)
Usage: cp [-f] [-i] [-p] f1 f2
cp [-f] [-i] [-p] f1 ... fn d1
cp -r|R [-f] [-i] [-p] d1 ... dn-1 dn

How can I use variable in this command?

Please advise.
Thank you.

check this option

Code:

awk -v

cp -p `ls -l *.* | awk '$6 ~ /$mon/{print $9}'` 0906

cp -p `ls -l *.* | awk -v '$6 ~ /$mon/{print $9}'` 0906 -- same error, where should I use the -v?

I hope that you will read about the option first and then try, but you did not. Something like this ?..

Code:

cp -p `ls -l *.* | awk -v mon="Jun"  '$6 ~ /mon/ {print $9}'`

Hi,

Thanks for the response. Tried as below.

# cp -p `ls -l *.* | awk -v mon="Jun" '$6 ~ /mon/ {print $9}'` 0906
awk: syntax error near line 1
awk: bailing out near line 1
cp: Insufficient arguments (1)
Usage: cp [-f] [-i] [-p] f1 f2
cp [-f] [-i] [-p] f1 ... fn d1
cp -r|R [-f] [-i] [-p] d1 ... dn-1 dn

I need to use variable instead of hardcode the month, appreciate someone can guide me on this. Thank you.