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awk date and time validation

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# 8  
Old 05-31-2009
Could somebody anwser?

-----Post Update-----

Could somebody anwser?
# 9  
Old 06-02-2009
Quote:
To check if February connection to the year is ok ,the value of the day according to any month ,the value of the month and simularlly like this to do for the time.
I know that in a foreign language, it is difficult to express exactly what you want.

You want input as "dd/mm". So today would be "02/06", correct? Then you want to make sure 02 is a valid day in 06?

Say you get "ddmm" and "hhmmss" as variables in your shell-script. (How you get them is up to you.)

Code:
DD=${ddmm%/*}
MM=${ddmm#*/}
hh=${hhmmss%%:*}
mmss=${hhmmss#*:}
mm=${mmss%:*}
ss=${mmss##*:}
echo $DD-$MM  $hh:$mm:$ss

So now you have it separated into parts. So now you just have to figure out if it's valid:
Code:
let invalid=0
case $MM in 
  02) 
          test $DD -le 29 || invalid=1 ;;
  0[469]|11) 
          test $DD -le 30 || invalid=1 ;;
  0[13578]|1[02]) 
          test $DD -le 31 || invalid=1 ;;
  *)
          invalid=1 ;;
esac

Note, I haven't tested this, so you better validate this before you use it in anything important.
# 10  
Old 06-02-2009
What with the case of year that february has 28 days?

-----Post Update-----

IN did it could be 28 or 29.

-----Post Update-----

IN did it could be 28 or 29.
# 11  
Old 06-02-2009
Yeah, but they're not providing the year.
# 12  
Old 06-03-2009
In my script the year is taken automatically by the computer without any input needed of year.
# 13  
Old 06-03-2009
Fine then. Just use standard algorithms to determine if the year is a leap year. If so, 29 is ok. If not, 28 is. Every 4 years from now is a leap year until 2100, which isn't.
# 14  
Old 06-03-2009
You could use use touch...
Code:
$ if touch -t 0902290000 file1 2> /dev/null; then echo okay; else echo not valid; fi
not valid

$ if touch -t 0902280000 file1 2> /dev/null; then echo okay; else echo not valid; fi
okay

If using awk...
Code:
$ awk 'BEGIN{if(!system("touch -t 0902290000 file1 2> /dev/null")) print "okay"; else print "not valid"}'
not valid

$ awk 'BEGIN{if(!system("touch -t 0902280000 file1 2> /dev/null")) print "okay"; else print "not valid"}'
okay
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