Shell Programming and Scripting

I have a script called S1.sh This script calulates the current seconds since epoch time and then gives me the current time.

S1.sh

Code:

#!/bin/ksh
set -x
TZ=`date +%Z`+0 ;a=`date +%Y-%m-%d`
echo $a

current_time=`date +%s`
echo "$current_time"
perl -le 'print scalar localtime('$current_time');' | awk '{print $4}' | cut -c 1-5

The problem here is the below command in the script giving the wrong time but when i type the same command in the command prompt it gives the correct result

In the script

Code:

perl -le 'print scalar localtime('$current_time');' | awk '{print $4}' | cut -c 1-5

output:
8:49

In the command prompt. let say the seconds are i.e. $current_time = 1241513359

Code:

perl -le 'print scalar localtime(1241513359);' | awk '{print $4}' | cut -c 1-5

output:
3:49

Hi
You can simply use this instruction to get current time
Cheers