Detecting Doublequotes(") When passed as parameter to shell script


 
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# 1  
Old 03-31-2009
Detecting Doublequotes(") When passed as parameter to shell script

Hi,

I am executing a shell script which takes a string as a parameter.
The scipt should validate the string and create the directoy with the name of specfied string.

The following is the specified command and its parameter.

test.sh "abc abc"

The shell script is not able to identify that the parameter "abc abc" as a single parameter. It takes the input as 2 parameters as it cannot identify the quotes (") specified.

Please suggest me how can I identify that qoutes have been specified as the input parameter.

So, if I am able to identity the quotes in the input parameter then I will throw an error in the cases where input "abc abc" or similar is given.

Thanks in advance
Raghu
raghu.amilineni
# 2  
Old 03-31-2009
let it take as 2 parameters...

in the shell script

do this..

str= `echo "$1 $2"`
# 3  
Old 03-31-2009
double post

Last edited by c_d; 03-31-2009 at 02:25 PM.. Reason: double post
# 4  
Old 03-31-2009
Question Not sure if I understand

See the following, where it appears the shell is taking everything inside quotes as one parameter.

Code:
> cat file8.sh
echo $#
echo $*
echo "1="$1
echo "2="$2

> file8.sh a b
2
a b
1=a
2=b

> file8.sh "a b"
1
a b
1=a b
2=

# 5  
Old 04-01-2009
Thanks for the reply ,

But I dont want to throw error if user specified " as part of the argument.
raghu.amilineni
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