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Shell Programming and Scripting

Substitution

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# 1  
Old 03-10-2009
Substitution
All,

I have this text document that contains a listing(See below).

What i would like to ask is how i could extract just the information i need which is the files name (CWS*****.***.gz)

If anyone has any suggestions i would be very grateful. I am sure its relatively simple but i just cannot figure out how to do it..

Thanks



Current Listing
/home/pilga/systems/mcc/outbound/CWS1111A.ABC.gz
/home/pilga/systems/mcc/outbound/CWS2222A.ABC.gz

New Listing
CWS1111A.ABC.gz
CWS2222A.ABC.gz
# 2  
Old 03-10-2009
Code:
awk -F\/  '{print $7}' < $yourFile > $youNewFile

# 3  
Old 03-10-2009
Code:
sed 's#.*/##' currentListing > newListing

# 4  
Old 03-10-2009
Quote:
Originally Posted by Digby
Code:
awk -F\/  '{print $7}' < $yourFile > $youNewFile

... and if the paths are longer OR if they are relative?
Code:
awk -F'/'  '{print $NF}' < $yourFile > $youNewFile

# 5  
Old 03-10-2009
Quote:
Originally Posted by vgersh99
... and if the paths are longer OR if they are relative?
Code:
awk -F'/'  '{print $NF}' < $yourFile > $youNewFile

Thanks, I knew there would be something like this... never looked into it.
# 6  
Old 03-11-2009
Code:
sed 's/\(.*\/\)\(CWS.*\..*\.gz\)/\2/' a.txt

# 7  
Old 03-11-2009
Power
Cheers for the solutions........God i need to get my head round this scripting stuff!!!!!
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