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Shell Programming and Scripting

menu selections

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# 1  
Old 03-03-2009
menu selections
I am trying to find a way to allow users to select multiple options in a shell menu. I am using case and it gives menu options 1-9, how can I set this up so that it give the user the ability to choose more then one option, ie 1,2 or 3,4,5, etc...
# 2  
Old 03-03-2009
hi,

giving multiple options to select is a little tricky. This is what you can try:
in your case, have 'q' to quit selection, and until 'q' is selected, loop to display menu, for every selection that is made, save it in an array.

Hope I was clear this helps.

Regards,
Kunal parmar
# 3  
Old 03-03-2009
Quote:
Originally Posted by parmar.kunal
hi,

giving multiple options to select is a little tricky. This is what you can try:
in your case, have 'q' to quit selection, and until 'q' is selected, loop to display menu, for every selection that is made, save it in an array.

Hope I was clear this helps.

Regards,
Kunal parmar

I think I understand, but do you have any examples? Is there an industry name for this type of operation?
# 4  
Old 03-03-2009
Code:
printf "%s\n" "MENU" "  1. qwerty" "  2. uiop" "  3. asdf" "  4. ghjkl"
printf "%s: " "Your choice (separate multiple selections with a comma)"

read selection

selection=$selection,
while [ -n "$selection" ]
do
   opt=${selection%%,*}
   echo "You selected: $opt"
   selection=${selection#*,}
done

# 5  
Old 03-03-2009
Thanks! I will give this a try in a bit.
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